posted by .

if x+ a= b/3x and b does not = 3 then x =?

i cant seem to find a way to seprate the two x's since 3/b is always attached.

subtract (b/3)x from both sides

x- (b/3) x+a=0
x(1-b/3)= -a

x= a/(1-b/3)

i looked at the back of my book and the answer is 3a/b-3

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    can anyone help me with these 3 problems I am trying to check my daughters hoime work it has bee na few years. 1. The sum of n and twenty -two, multiplied by three, is 78 2. the product of z and 17 is less than or equal to the difference …
  2. math

    the radius of a circle when the numeric values of the circumference and area are equal. circumference = 2*pi*r area = pi*r^2 Set them equal and solve for r. thanks! i understand it now! 2*3.14*r=3.14*r^2 6.28*r=3.14*r^2 r=3.14 Is that …

    m-2/m-5*m+5/m-2=-1 If your problem is this: (m - 2)/(m - 5) * (m + 5)/(m - 2) = -1 (m - 2) cancels out in both the numerator and denominator on the left-hand side since you are multiplying. That leaves us with this: (m + 5)/(m - 5) …
  4. math

    Solve each formula for n. 2n = 4xp-6 3m-n=4s r/n+2=p t=100(n+3) pv/nR=T 8a+2=6b In the first example, divide both sides of the equation by 2 In the second example, add n to both sides of the equation. Try these yourself. They aren't …
  5. math

    I need help figuring out these two questions on euations with integers. -5x+20=-60 2x-3=-2 thank you so much for first: subtract 20 from both sides, simplify, then divide both sides by -5 for second: add 3 to both sides, simplify, …
  6. Algebra

    How can I transform the equation 4=x-y into one that begins with "y="?
  7. Algebra Repost

    How can I transform the equation 4=x-y into one that begins with "y="?
  8. Algebra

    Why are these algebraic expressions used and explain the logical error: Since a = b, then a2 = a * b Subtract b2 from both sides a2 – b2 = a * b – b2 Factor both sides: ( a + b )( a – b ) = b(a – b ) Divide both sides by ( …
  9. ALgebra

    Indicate and explain the logical error in the following set of algebraic expressions Let a=b square both sides to get a^2=b^2 a^2=b*b Since a=b, then a^2=a*b Subtract b^2 from both sides a^2-b^2=a*b-b^2 Factor both sides: (a+b)(a-b)=b(a-b) …
  10. Algebra

    Which of the following describes a correct method for solving the equation below?

More Similar Questions