# math/algebra

posted by Diana

2/5 - y/y-2
a)-3y-2/y-2
b) -3y -2/5(4-2)
c) -3y-4/5(y-2)
d) -3y-4/y-2

The way you have written the problem, is 2/5 minus y^3. I don't think that is what you meant. Please use grouping symbols on fractions () or []

The way you have written the problem, is 2/5 minus y^3. I don't think that is what you meant. Please use grouping symbols on fractions () or []

it if a fraction 2/5 - y/(y-2)

common denominator: 5(y-2)

2y-4 -5y is the numerator (you need to combine)

I came up with -3y-4/5(y-2) is this correct?

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Can someone verify if my answers are correct?

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