What would three points on a graph be, graphing the x and y intercepts, with the equation -x + 3y = -9?
The x and y intercepts are what you get when plugging in y=0 or x=0. For a third point, you can choose any other x or y value you want and compute the other coordinate
To find the x-intercept, we can set y equal to zero in the equation -x + 3y = -9.
Plugging in y = 0, we get:
-x + 3(0) = -9.
Simplifying further:
-x + 0 = -9,
-x = -9,
x = 9.
Therefore, the x-intercept is (9, 0).
To find the y-intercept, we can set x equal to zero in the equation -x + 3y = -9.
Plugging in x = 0, we get:
-0 + 3y = -9.
Simplifying further:
3y = -9,
y = -9/3,
y = -3.
Therefore, the y-intercept is (0, -3).
To find a third point on the graph, we can choose any value for either x or y and compute the other coordinate using the equation -x + 3y = -9.
For example, let's choose x = -1.
Substituting x = -1 into the equation, we get:
-(-1) + 3y = -9.
Simplifying further:
1 + 3y = -9,
3y = -10,
y = -10/3.
Therefore, another point on the graph is (-1, -10/3).
So the three points on the graph, graphing the x and y-intercepts, with the equation -x + 3y = -9, are:
(9, 0), (0, -3), and (-1, -10/3).