# math

posted by
**jason**
.

solve the equation x^3-5x^2-4x+20=0

I need a hint on how to solve this

Look for the first root by graphical means or trial-and-error. Note that when x=2,

x^3-5x^2-4x+20 = 8-20 -8 +20 = 0.

Therefore 2 is one root and x-2 is a factor.

Next, divide x-2 into x^3-5x^2-4x+20 using long division, to get a quadratic factor. The result is

(x-2)(x^2-3x-10)

The quadratic factor is just (x-5)(x+2), so the equation becomes

(x-2)(x+2)(x-5) = 0

This tells you that the other roots are x = -2 and +5.