math,correction, bobpursly
posted by bobpursley .
Since when is 5^7 =8125?
if a number is a multple of ten, that means the last digit is zero. The leading digit cannot be zero.
9*10^5*1
on c, again, the leading digit cannot be zero.
d is right
e. no leading zero is allowed. 9*9*8*7*6*5*4= ?
can someone correct this for me parts AE and if i am wrong can you help me....please
How many 7digit telephone numbers are possible if the first digit cannot be zero and.....
a) only odd digits may be used?
5^7= 8125
my answer: 8125
b) the telephone number must be multiple of 10(that is , it must end in zero)?
10^6*1=1,000,000
my answer: 1,000,000
c) the telephone number must be a multiple of 100?
10^5*1*1=100,000
my answer 100,000
d) the first 3 digits are 481?
1*1*!*10^4=10,000
my answer 10,000
e) no repetitions are allowd?
10 combination 7 = 120
my answer: 120
oops for the part a: 5^7 = 78125
part e: 544320
i need help with c
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