John's present age is five years more than thrice the present age of his son. Five Years hence, John's age will be fifteen years more than twice the age of his son at that time. Find the present age of John and his son.
J=3*S +5
J+5=15+2*(S+5)
Find J
Son's age is 15
Father's age is 50
To find the present age of John (J) and his son (S), we will solve the given system of equations:
Equation 1: J = 3S + 5 (John's present age is five years more than thrice the present age of his son)
Equation 2: J + 5 = 15 + 2(S + 5) (Five years hence, John's age will be fifteen years more than twice the age of his son at that time)
To solve this system of equations, we will substitute Equation 1 into Equation 2:
(3S + 5) + 5 = 15 + 2(S + 5)
3S + 10 = 15 + 2S + 10
3S + 10 = 2S + 25
Next, we will simplify the equation:
3S - 2S = 25 - 10
S = 15
Now that we have the value of S, we can substitute it back into Equation 1 to find J:
J = 3S + 5
J = 3(15) + 5
J = 45 + 5
J = 50
Therefore, the present age of John is 50 and the present age of his son is 15.