Algebra
posted by Tomika .
Find the axis of symmetry
y=x^27x+2
Well, it's a parabola. If you rewrite the equation by completing the square, you get
y = (x  7/2)^2 + 2  (7/2)^2
= (x  7/2)^2  41/4
It will be symmetric about the x = 7/2 line and the minimum will be at y = 41/4.
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