posted by Camila .
Can someone please explain this problem to me? I would appreciate it very much.
1. y=x^2 - 2mx + (2m + 3)
2. D= b^2 - 4ac
3. D= (-2m)^2 - 4(1)(2m - 3)
4. 4m^2 - 8m + 12
5. 4(m^2 - 2m + 3)
6. 4(m + 1)(m - 3)
m (> or = to) 3, m (< or = to) -1
Then you draw the parabola with the roots -1 and 3 and shade the outside positive regions.
This problem is about finding out for which m the function:
y=x^2 - 2mx + (2m + 3)
has two zeros. This is the case if and only if D > 0.
If D > O, then why would m be > or = and not just >?
you are correct. If D>zero, it has two roots, and m >0 for two distinct roots.
OK, thanks! I was really confused with the whole problem! Thank you both for your help.