Precal
posted by Tri .
what is your answer for 8sin^2theta + sintheta 1 ?
and how would you do it ? thanks
You have not written an equation. There is nothing to "solve". Did you leave out an " = 0 " ?
Yeah sorry
Yeah sorry
Let x = sin theta
8x^2 +x 1 = 0
x = [1 +/ sqrt(33)]/16
= 0.296535 or 0.421535
theta = 17.250 degrees or 24.931 degrees
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