Directions:Write inequalities for the numbers 2 - 4 below. Do not solve them!
Problems:
2.Your quiz grades are 19, 17, 20, and 15. What is the lowest grade you can receive on the next quiz and maintain at least an 18 average?
3.Stacey and Luis volunteer at the local hospital. Stacey worked 4 more hours than Luis, and together they worked more than 28 hours. What is the least number of hours each worked?
4.Mrs. Culpepper has promised her two sons that they may go to a concert if together they save more than $45. The older son agrees to save twice as much as the younger one. How much must each save?
I will do one as an example. I will be happy to critique your work.
4> O=2Y
O+ Y>45
2Y+Y>45
3Y>45
Y>15 and O=2Y. So Y is the determinante for O. If Y saves 25, O has to save 50.
I will do one as an example. I will be happy to critique your work.
4> O=2Y
O+ Y>45
2Y+Y>45
3Y>45
Y>15 and O=2Y. So Y is the determinante for O. If Y saves 25, O has to save 50.
2. Let x be the lowest grade on the next quiz.
(19 + 17 + 20 + 15 + x) / 5 ≥ 18
3. Let L be the number of hours Luis worked.
L + (L + 4) > 28
4. Let Y be the amount the younger son saves and O be the amount the older son saves.
Y + O > 45
O = 2Y
2. Let x be the lowest grade on the next quiz.
Since the average grade should be at least 18, the sum of all grades should be greater than or equal to (18 * 5), which is 90.
So, the inequality can be written as:
19 + 17 + 20 + 15 + x ≥ 90
3. Let L be the number of hours Luis worked.
Since Stacey worked 4 more hours than Luis, let S = L + 4 be the number of hours Stacey worked.
Together, they worked more than 28 hours, so the sum of their hours should be greater than 28.
The inequality can be written as:
L + (L + 4) > 28
4. Let Y be the amount the younger son saves.
Since the older son agrees to save twice as much as the younger one, the amount saved by the older son can be written as O = 2Y.
Together, they must save more than $45, so the sum of their savings should be greater than 45.
The inequality can be written as:
Y + O > 45
Y + 2Y > 45
3Y > 45
Note: It seems there is a mistake in your example solution for problem 4. Y should be the determinant for O, not the other way around. If Y saves 25, O should save 2Y, which is 50.