calculate the speed of the pendulum at its lowest point if its PE is 5J at its heighest point and has a total mass of 1kg.

5 Joules = (1/2) M V^2 at lowest point.

Solve that equation for V at lowest point.

To calculate the speed of the pendulum at its lowest point, we can use energy conservation principles. The potential energy (PE) at the highest point is equal to the kinetic energy (KE) at the lowest point.

The formula for potential energy is given by:

PE = mgh

Where m is the mass of the pendulum, g is the acceleration due to gravity, and h is the height. In this case, the potential energy at the highest point is given as 5 Joules.

Now, the formula for kinetic energy is given by:

KE = (1/2)mv^2

Where m is the mass of the pendulum and v is the velocity. We want to find the velocity at the lowest point.

Since the potential energy at the highest point is equal to the kinetic energy at the lowest point, we can set up the equation:

PE = KE

5 J = (1/2)(1 kg)v^2

Now, we can solve for v by rearranging the equation:

v^2 = (2 * 5 J) / 1 kg
v^2 = 10 J / 1 kg
v^2 = 10 m^2/s^2
v = √(10 m^2/s^2)

Therefore, the speed of the pendulum at its lowest point is approximately 3.16 m/s.