sorry mr bob pursley to annoy you again.

i read over hooke's law in wikipedia.but i don't know what is k.(my force constant.

here my experiment and my values.
i did three trials measured force applied of the elastic by streching 50 cm everytime.
force applied average was = 5.86N ( average of three trials)
average elastic pulled= 50cm (average of three trials)
averagedistance travelled by wooden block= 0.0685m=6.8m
where hook law states
x= 50cm
k=5.8 force constant (am i right) is this spring constant)
f= am i solving for this

sorry again and thank you.

k=forceapplied/distancestretched
k=5.86N/.5m= 11.7 N/m

Now, the distance traveled should include the rubber band stretching distance, as fricion is operating there also.

1/2 (11.7N/m)(1/2)^2= avgforcfriction*distance slid

I don't know in the distance slid above if you included the 1/2 meter that the band was stretched, at any rate, you solve for averagefriction force.

No problem, happy to help again! Let's break down the information and calculate the force constant (k) or spring constant.

Based on your experiment:

Force applied average = 5.86N (average of three trials)
Average elastic pulled = 50cm (average of three trials)
Average distance traveled by the wooden block = 6.8m

To calculate the force constant (k), you need to use Hooke's law, which relates the force applied to the displacement of the material.

Hooke's law formula: F = k * x

Where:
F is the force applied
k is the force constant or spring constant
x is the displacement

In your case, you have x = 50 cm = 0.5 m and F = 5.86 N. Plugging these values into the formula, we can solve for k:

k = F / x
k = 5.86 N / 0.5 m
k ≈ 11.7 N/m

So the force constant or spring constant is approximately 11.7 N/m.

Now, for the equation 1/2 (11.7N/m)(1/2)^2 = avgforcfriction * distance slid, it seems like you are trying to calculate the average friction force. However, it's not clear what the "distance slid" represents in your experiment. If you provide more information, I can help you further with that calculation.