Predict the order of increasing vapor pressure (at a given temperature) for the following compounds: FCH2CH2F and FCH2CH2OH and HOCH2CH2OH. Explain your decision briefly.
ANSWER: I suppose the order is FCH2CH2F and FCH2CH2OH and HOCH2CH2OH (increasing from left to right)Increasing the temperature increases the vapor pressure. I believe it has to do with what molecules are bonded to the carbons and their nature.
ya that's good
Pleas answer....?
Antoine equation to Glucose (C6H12O6)?
Well, I'm glad you think so! But allow me to elaborate a bit more. The vapor pressure of a compound is determined by its intermolecular forces, specifically the strength of its molecular interactions.
In this case, we have three compounds: FCH2CH2F, FCH2CH2OH, and HOCH2CH2OH. The first compound, FCH2CH2F, is a nonpolar molecule because it only contains fluorine atoms and carbon atoms. Nonpolar molecules have weaker intermolecular forces, so it will have the lowest vapor pressure.
Moving on to FCH2CH2OH, which is an alcohol. The presence of the hydroxyl group (-OH) adds polarity to the molecule, making it more attracted to other molecules. Consequently, the intermolecular forces are stronger than in FCH2CH2F, resulting in a higher vapor pressure.
Finally, we have HOCH2CH2OH, which is also an alcohol but with the addition of an extra hydroxyl group. The presence of two hydroxyl groups further increases the polarity of the molecule and enhances the intermolecular forces, making it the compound with the highest vapor pressure.
So, to sum it up, the order of increasing vapor pressure would be FCH2CH2F < FCH2CH2OH < HOCH2CH2OH.
To predict the order of increasing vapor pressure at a given temperature for the compounds FCH2CH2F, FCH2CH2OH, and HOCH2CH2OH, we need to consider the intermolecular forces present in each compound.
In general, vapor pressure is influenced by the strength of the intermolecular forces. Higher intermolecular forces tend to result in lower vapor pressure.
FCH2CH2F is a fluorinated alkane, which means it only experiences weak dispersion forces between its molecules. The only intermolecular force present is London dispersion forces.
FCH2CH2OH, on the other hand, is an alcohol. It has a polar OH group, which allows for hydrogen bonding between its molecules in addition to London dispersion forces. Hydrogen bonding is stronger than London dispersion forces.
HOCH2CH2OH is also an alcohol, which means it can also exhibit hydrogen bonding. However, in this case, there is an additional -OH group present, which allows for the formation of more hydrogen bonds compared to FCH2CH2OH. Therefore, HOCH2CH2OH will have stronger intermolecular forces than FCH2CH2OH.
Since stronger intermolecular forces generally result in lower vapor pressure, the order of increasing vapor pressure at a given temperature is FCH2CH2F < FCH2CH2OH < HOCH2CH2OH.
To predict the order of increasing vapor pressure for the given compounds (FCH2CH2F, FCH2CH2OH, and HOCH2CH2OH) at a given temperature, we need to consider the intermolecular forces within the molecules.
The vapor pressure of a compound is mainly determined by the strength of the intermolecular forces holding the molecules together. Generally, weaker intermolecular forces result in higher vapor pressures.
Comparing the given compounds, FCH2CH2F and FCH2CH2OH both have London dispersion forces as the primary intermolecular force. However, FCH2CH2OH also exhibits hydrogen bonding due to the presence of an alcohol group (OH). Hydrogen bonding is a stronger intermolecular force than London dispersion forces.
Next, comparing FCH2CH2OH and HOCH2CH2OH, both have hydrogen bonding among their intermolecular forces. However, HOCH2CH2OH has two alcohol groups, while FCH2CH2OH has only one. Therefore, the presence of two alcohol groups enhances hydrogen bonding, making HOCH2CH2OH have stronger intermolecular forces and a lower vapor pressure.
Based on this analysis, we can predict the order of increasing vapor pressure to be FCH2CH2F < FCH2CH2OH < HOCH2CH2OH. This means that the compound FCH2CH2F is expected to have the highest vapor pressure, followed by FCH2CH2OH, and the compound HOCH2CH2OH will have the lowest vapor pressure at a given temperature.
HOCH2CH2OH, FCH2CH2OH, FCH2CH2F
because of decreased hydrogen bonding from left to right