The electric field between two charged plates is 2000N/C. What is the voltage difference if the plates are separated by a distance of 1.0 x 10^-4 m?
I know that the answer is supposed to be .2 volts but I have no idea what formula to use??? can anyone help?!
E*distance= voltage or
E= changeinvoltage/distance
Formulas sure help. Bob knows many!
To find the voltage difference between two charged plates, you can use the formula:
Voltage (V) = Electric Field (E) * Distance (d)
In this case, the electric field is given as 2000 N/C and the distance between the plates is 1.0 x 10^-4 m. Plugging these values into the equation, we get:
V = 2000 N/C * (1.0 x 10^-4 m)
To solve this problem, you need to multiply the electric field by the distance. However, it seems like you made a mistake when setting up the calculation. Notice that the units in the electric field (N/C) cancel out with the units in the distance (m), leaving you with volts (V). Therefore, the voltage difference should be calculated as follows:
V = 2000 N/C * 1.0 x 10^-4 m
= 2000 * 1.0 x 10^-4 N*m/C
= 200 * 10^-4 N*m/C
= 200 * 10^-4 V
= 0.2 V
So, the correct answer is 0.2 volts, not 0.2.