How many atoms are in 12g of Zinc?

There are 6.02 x 10^23 atoms in 1 mol of anything. 1 mol of Zn has a mass of 65.38 g so 12 g is what part of a mol of Zn? and that fraction x 6.02 x 10^23 will be the number of atoms of Zn in the 12 g Zn.

To find the number of atoms in 12g of Zinc, you need to determine the fraction of a mole that 12g represents and then multiply it by Avogadro's number (6.02 x 10^23).

First, calculate the number of moles of Zinc in 12g:
Molar mass of Zinc (Zn) = 65.38 g/mol
Number of moles = mass/molar mass = 12g/65.38 g/mol

Now, find the fraction of a mole that 12g represents:
Fraction of a mole = 12g/65.38 g/mol

Finally, calculate the number of atoms in 12g of Zinc:
Number of atoms = Fraction of a mole x Avogadro's number
Number of atoms = (12g/65.38 g/mol) x (6.02 x 10^23)

Performing this calculation will give you the number of atoms in 12g of Zinc.

To determine the number of atoms in 12g of Zinc, you can follow these steps:

1. Calculate the number of moles of Zinc in 12g. To do this, divide the given mass (12g) by the molar mass of Zinc (65.38g/mol):

Moles of Zinc = 12g / 65.38g/mol

2. Determine the fraction of a mole represented by 12g of Zinc. This can be calculated by dividing the moles of Zinc by the number of moles per mole (Avogadro's number):

Fraction of a mole = Moles of Zinc / (6.02 x 10^23)

3. Finally, multiply the fraction of a mole by Avogadro's number to obtain the number of atoms in 12g of Zinc:

Number of atoms = Fraction of a mole x (6.02 x 10^23)

By following these steps, you can find the answer to the question.