Calculus
posted by Anonymous .
R=M^2(c/2m/3)
dR/dM=CMM^2
I found the derivative. Now how would I find the vale of M that maximize the derivative dR/dM?
set it to zero, and solve for m. You get two solutions. Use the second derivative to see which one is the max.
I get M=C. How do I go from there? What do I do?
M=C is one of the solutions for a max/min. Use the second derivative to see which. M=0 is the other.
how can you tell which is the max/min? They are both variables. c=positive constanct, m=amt of medicine absorbed in the blood, dR/dM=sensitivity of the body of medicine
How do you get m=0? from taking the second derivative? does c=1?
Can you check my work on how I get the derivative of R=M^2(c/2m/3) NEXT R=1/2(CM^2)1/3(M^3) NEXT dR/dM=CMM^2. I checked in the back, and that was the answer for the first part of the equation. Isn't the derivative of constant c, zero? I am confused.

C is a constant so you use the product rule.
2m(c/2m/3)+m^2(1/3)
2m being the derivative of m^2. times the original second term. then the derivative of the second term times the original first.
1/3 being the derivative of the (c/2m/3) because C is a constant