# algebra

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write (27a^-3)^(-2/3) in simplest form.

solve log(6x+11)=2

I am not going to give you the answers. I will be happy to critique your work.

In the first, remember that (a^b)^c= a^bc

I am not looking for the answers.

And I told you:

I'm not quite sure what to do for the first, but this is what I tried to do:

(27a^-3)^(-2/3)
=the cubed root of (27a^-3)^-2
=the cubed root of 27^-2*a^6

and

what is the antilog?

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