How would I solve the following integral with the substitution rule?

Integral of: [(x^3)*(1-x^4)^5]dx

Put 1-x^4 = y

Then -4x^3 dx = dy

Integral is then becomes:

Integral of -1/4 y^5 dy

ok, thanks a lot! I got it now.

integrals of S 2-4 ((3*y^5)/(5*(y^3 -2)^(1/4)))*dy

You're welcome! I'm glad I could help. Just to complete the solution, the integral of -1/4 y^5 dy can be easily calculated using the power rule for integration. Applying the power rule, we can rewrite the integral as:

-1/4 * [y^6/6] + C

Substituting y back with 1-x^4, we get:

-1/4 * [(1-x^4)^6/6] + C

And that is the final result of the integral.