# Math/Calculus

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How would I solve the following integral with the substitution rule?

Integral of: [(x^3)*(1-x^4)^5]dx

Put 1-x^4 = y

Then -4x^3 dx = dy

Integral is then becomes:

Integral of -1/4 y^5 dy

ok, thanks a lot! I got it now.

• Math/Calculus -

integrals of S 2-4 ((3*y^5)/(5*(y^3 -2)^(1/4)))*dy

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