# algebra

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write (27a^-3)^(-2/3) in simplest form.

solve log(6x+11)=2

I need to see your work on the first.

On the second, take the antilog of each side

what is the antilog?

I'm not quite sure what to do for the first, but this is what I tried to do:

(27a^-3)^(-2/3)
=the cubed root of (27a^-3)^-2
=the cubed root of 27^-2*a^6

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