algebra
posted by think I got it .
Given f(x) = 2x  5, find f(3a).
F(x)= 2(3a) 5
F(3a) = 2(3a)5
= 1
did I do this right?
You went from:
f(3a)
to
f(3a)
Also, what happened to the "a?"
Matt
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