Given f(x) = 2x - 5, find f(-3a).
F(x)= 2(-3a) -5
F(-3a) = 2(3a)-5
= 1
did I do this right?
You went from:
f(-3a)
to
f(3a)
Also, what happened to the "a?"
Matt
To find f(-3a), you need to substitute -3a into the function f(x) = 2x - 5.
So, you did the first step correctly by substituting -3a into x:
f(-3a) = 2(-3a) - 5
However, in the next step, it seems like you made a mistake.
To simplify further, you need to distribute the 2 to -3a:
f(-3a) = -6a - 5
So, your final answer for f(-3a) is -6a - 5, not 1.