6x sq.-5x-1=0
use the equation of the squre if u want to solve it.
use the quadratic formula
Please read:
http://en.wikipedia.org/wiki/Quadratic_equation
Or
http://mathworld.wolfram.com/QuadraticFormula.html
how can i do fractons and i need some advised
First, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where is more likely to be overlooked.
I searched Google under the key words "math fractions" to get these possible sources:
http://www.aaamath.com/fra.html
http://www.coolmath4kids.com/fractions/
http://www.kidsolr.com/math/fractions.html
http://home.avvanta.com/~math/FDMENU.HTM
http://math.rice.edu/~lanius/fractions/index.html
In the future, you can find the information you desire more quickly, if you use appropriate key words to do your own search.
I hope this helps. Thanks for asking.
To solve the equation 6x^2 - 5x - 1 = 0, we can use the quadratic formula.
The quadratic formula is given by x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the equation ax^2 + bx + c = 0.
For the equation 6x^2 - 5x - 1 = 0, we have a = 6, b = -5, and c = -1.
Plugging these values into the quadratic formula, we get:
x = (5 ± √((-5)^2 - 4(6)(-1))) / (2(6))
Simplifying further:
x = (5 ± √(25 + 24)) / 12
x = (5 ± √(49)) / 12
x = (5 ± 7) / 12
This gives us two solutions:
x = (5 + 7) / 12 = 12 / 12 = 1
and
x = (5 - 7) / 12 = -2 / 12 = -1/6
Therefore, the solutions to the equation 6x^2 - 5x - 1 = 0 are x = 1 and x = -1/6.
To solve the equation 6x^2 - 5x - 1 = 0 using the quadratic formula, you can follow these steps:
Step 1: Identify the coefficients a, b, and c in the equation. In this case, a = 6, b = -5, and c = -1.
Step 2: Write down the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
Step 3: Substitute the values of a, b, and c into the quadratic formula:
x = (-(-5) ± √((-5)^2 - 4(6)(-1))) / (2(6))
Simplifying this expression further:
x = (5 ± √(25 + 24)) / 12
x = (5 ± √49) / 12
Step 4: Simplify the square root:
x = (5 ± 7) / 12
Step 5: Split the equation into two solutions:
x₁ = (5 + 7) / 12 = 12 / 12 = 1
x₂ = (5 - 7) / 12 = -2 / 12 = -1/6
Therefore, the solutions to the equation 6x^2 - 5x - 1 = 0 are x = 1 and x = -1/6.
To further understand the quadratic formula and its derivation, you can read the articles provided in the links:
- http://en.wikipedia.org/wiki/Quadratic_equation
- http://mathworld.wolfram.com/QuadraticFormula.html
Regarding fractions, if you need help and advice, you can ask specific questions about fractions or consult the following websites for more guidance:
- http://www.aaamath.com/fra.html
- http://www.coolmath4kids.com/fractions/
- http://www.kidsolr.com/math/fractions.html
- http://home.avvanta.com/~math/FDMENU.HTM
- http://math.rice.edu/~lanius/fractions/index.html
Remember to ask new questions separately for better visibility and response.