Math
posted by Mack .
3,5,5...
The first term in the sequence of #'s shown above is 3. Each even # term is 2 more than the previous term and each odd # term, after the first, is 1 times the previous term. For example, the second term is 3+2, and the third term is (1)x5. What is the 55th term of the sequence?
a.5
b.3
c.1
d.3
e.5
The Answer is: (A)5 H0w did they arrive at that answer???
lets look at the sequence. Check me.
3,5,5,3,3,5,5, 3, 3, 5, 5, ..
Notice the terms 3, 7, 11 are all 5. So one can predict that the thirteenth term, 17, 21 term and so on will be 5.
Each fourth term after the third is 5.
the 20 +3 term is 5 spaces of 4's after 3, the 40 + 3 term is 10 spaces of 4, the 52+3 term is 13 spaces of 4, so that means the 55 term is 5
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