chem-balancing acidic equation
posted by alexa .
Cr2O7^-2(aq) + Cl- -> Cr^3+(aq) + Cl2(g)
Cr2O7^-2(aq)+14H+ +6e- -> 2Cr^3+(aq)+7H2O
Cl- -> Cl2(g)
2Cl- -> Cl2 +2e-
Cr2O7^-2(aq)+14H+ +6e- +2Cl- -> 2Cr^3+(aq)+7H2O +Cl2 +2e-
Cr2O7^-2(aq)+14H+ +4e- +2Cl- -> 2Cr^3+(aq)+7H2O +Cl2
However, the answer to the number of total coefficients is 33, and i got 31. What am I missing?
Just at first glance, did you multiply the 2Cl--> Cl2 + 2e by 3 to make electrons gained = electrons lost. I don't see the 3 anywhere. But I didn't check that to see if the coefficients added to 33.
Yes, that makes the sum of the coefficients 33.
ohhhhhhh....duh i always forget that part at the end to make them equal jeesh thank you