If the distance between two slits is 0.0620 mm find the angle between the second and third order bright fringe for light with a wavelength of 503nm.
Is the answer 0.48?
http://www.walter-fendt.de/ph14e/doubleslit.htm
Find the angle for the k=2 max, then find the angle for k=3 max, ans subtract the angles to get the difference.
d sinTheta= k*l
I get 0.464932031 degrees. Check your work again, I could have made an error.
To find the angle between the second and third order bright fringe, you can use the formula d sin(theta) = k * lambda, where d is the distance between the two slits, lambda is the wavelength of light, theta is the angle between the bright fringe and the central maximum, and k is the order of the bright fringe.
Given that the distance between the two slits (d) is 0.0620 mm (or 0.0620 x 10^-3 m) and the wavelength of light (lambda) is 503 nm (or 503 x 10^-9 m), we can proceed to solve the equation.
For the second order bright fringe (k = 2), we have:
0.0620 x 10^-3 m * sin(theta2) = 2 * 503 x 10^-9 m
Simplifying, we get:
sin(theta2) = (2 * 503 x 10^-9 m) / (0.0620 x 10^-3 m)
sin(theta2) = 0.032145
To find theta2, we take the inverse sine of both sides of the equation:
theta2 = arcsin(0.032145)
Using a scientific calculator, we find:
theta2 ≈ 1.84 degrees
Similarly, for the third order bright fringe (k = 3), we have:
0.0620 x 10^-3 m * sin(theta3) = 3 * 503 x 10^-9 m
Simplifying, we get:
sin(theta3) = (3 * 503 x 10^-9 m) / (0.0620 x 10^-3 m)
sin(theta3) = 0.048218
To find theta3, we take the inverse sine:
theta3 = arcsin(0.048218)
Calculating this on the calculator, we find:
theta3 ≈ 2.77 degrees
To find the difference between the angles, we subtract theta2 from theta3:
angle difference = theta3 - theta2
angle difference ≈ 2.77 degrees - 1.84 degrees
angle difference ≈ 0.93 degrees
Therefore, the angle between the second and third order bright fringe for light with a wavelength of 503 nm and a slit distance of 0.0620 mm is approximately 0.93 degrees.