An unknown was prepared with the concentration of 0.000331 M. A Beer's Law plot was prepared using the absorbance values from standard solutions of ASA and a line drawn through all the points passed through the origin with a slope of 1646.3 M–1 . The expected absorbance and %T values for the diluted aspirin solution prepared by the student is
and , respectively.
i know u get the expected absorbance by just multiplying the concentration by the slope, but how do you get the %T (transmittance)?
What value did you obtain for A? Let's just make up a number, say A = 0.600
Then A = log (1/T)
0.600 = log (1/T)
Take the inverse log (the antilog) of both sides to give
3.98 = 1/T
and T = 1/3.98 = 0.251
and %T = 25.1%
To calculate the transmittance (%T) from the absorbance (A), you can use the following formula:
A = log(1/T)
Let's say you obtained a value of A = 0.600.
To find the transmittance (T), you take the inverse log (antilog) of both sides of the equation:
10^A = 1/T
In this case, 10^0.600 is approximately equal to 3.98. So we have:
3.98 = 1/T
Now, to calculate the transmittance, you take the reciprocal of 3.98:
T = 1/3.98 = 0.251
This means the transmittance is approximately 0.251 or 25.1%.
Hence, in this example, you obtained an absorbance of 0.600, which corresponds to a transmittance of approximately 25.1%.