The length of a rectangular garden is 5 ft less than 3 times its width. If the perimeter of the garden is 22 ft, find the dimensions of the garden.
I will start you off with...
let the width be w,
then the length is 3w - 5
I am pretty sure you can form the equation from there and solve it.
Let me know what you got.
2x +2(3x -5)= 22
2x + 6x -10 = 22
x = 4 then I'm lost where to I go from here?
so your width is 4 feet,
you called your length 3x-5 which is 3(4)-5 or 7 feet.
if somebody asks you for the "dimensions" of a field, they are asking for the length and width of the field.
the perimeter of a rectangle is 290 m. if the length is 5 m less than twice the width, find the demension of a rectangle
Great job so far! You have correctly found that the width of the garden is 4 feet and the length is 7 feet. So the dimensions of the garden are 4 feet by 7 feet.
Good job on finding the width of the garden, which is 4 feet.
Now, to find the length, you can substitute the value of the width (4) into the expression you had earlier:
Length = 3w - 5
= 3(4) - 5
= 12 - 5
= 7
So, the length of the rectangular garden is 7 feet.
To summarize, the dimensions of the garden are:
Width = 4 feet
Length = 7 feet