Write the equation of the line with slope –2 and y-intercept (0, 0). Then how do i graph this?
do i insert -2x 0y and then 2x 0y to make my graph?
To write the equation of a line with a given slope and y-intercept, we use the slope-intercept form of a linear equation, which is given by the equation: y = mx + b
In this case, the slope (m) is -2, and the y-intercept (b) is (0, 0). So, we can substitute these values into the equation as follows:
y = -2x + 0
Simplifying, we get:
y = -2x
To graph this line, you don't need to insert specific coordinates like -2x 0y or 2x 0y. Instead, you can use the slope to determine the direction of the line and the y-intercept to determine where the line crosses the y-axis.
Since the y-intercept is (0, 0), this means that when x is 0, y is also 0. So, one point on the line is (0, 0).
Next, you can use the slope to find another point on the line. The slope tells us that for every 1 unit increase in x, there is a 2 unit decrease in y. So, starting from the point (0, 0), you can move 1 unit to the right and 2 units down to find another point.
For example, starting from (0, 0), move 1 unit to the right, the x-coordinate becomes 1. Then, move 2 units down, the y-coordinate becomes -2. So, another point on the line is (1, -2).
Now, you can plot these two points, (0, 0) and (1, -2), on the graph and draw a straight line passing through them. Make sure to extend the line in both directions.
Your graph should show a line that passes through the points (0, 0) and (1, -2).