Chemistry

posted by .

srry I placed the question in the wrong spot.

The equation is
2NH3 <=> N2 + 3H2
1 mole of NH3 injected intoa 1L flask
0.3 moles of H2 was found
the concentration of N2 at equlibrium is 0.1M

how do I find the concentration of NH3 at equlibrium?

(N2) = 0.1
(H2) = 0.3
Amount NH3 used is 0.1 mol N2 x (2 mol NH3/1 mol N2) = 0.1 x 2/1 = 0.2 mol NH3 used.

OR you can start with 0.3 H2 like this;
0.3 H2 x (2 mol NH3/3 mol H2) = 0.2 mol NH3 used.

We started with 1 mol NH3; therefore, we have remaining 1.0-0.2 = 0.8 mol/L.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry``

    A substance (CD) decomposes into C and D. CD(g)  C(g) + D(g) At the temperature of the experiment, 15.0 percent of CD is decomposed when equilibrium is established. a) If the initial concentration of CD is 0.200 mol/L, …
  2. chemistry

    For the following reaction: 2NH3 ----> N2 + 3H3 6.42 moles of NH3 were placed in a 7.4 L flask and allowed to come to equilibrium. 3.60 moles of NH3 remain at equilibrium. Calculate Kc for the reaction.
  3. chemistry

    For the following reaction: 2NH3 ----> N2 + 3H3 6.42 moles of NH3 were placed in a 7.4 L flask and allowed to come to equilibrium. 3.60 moles of NH3 remain at equilibrium. Calculate Kc for the reaction.
  4. Chemistry

    One mole of N2 and three moles of H2 are placed in a flask at 375 C. Calculate the total pressure of the system at equilibrium if the mole fraction of NH3 is 0.21. The Kp for the reaction is 4.31*10^4. I assume this to be the reaction …
  5. Chemistry

    One mole of N2 and three moles of H2 are placed in a flask at 375 C. Calculate the total pressure of the system at equilibrium if the mole fraction of NH3 is 0.21. The Kp for the reaction is 4.31*10^4. I assume this to be the reaction …
  6. Chemistry - Kp

    What is the Kp for the following reaction: 2NH3(g) --> N2(g) + 3H2(g) This reaction is contained in 1.0 L container at 1,000 K and has reached equilibrium. (Kc = 4.0 x 10^-2). You have initially added 1,220 moles of NH3(g) in the …
  7. Chemistry

    A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) --> N2(g) + 3H2(g) At equilibrium, it was found that the concentration of H2 was 0.0584 M, the concentration of N2 was 0.0195 M, and the concentration …
  8. Chemistry

    One mole of N2 and 3 moles of H2 are placed in a flask at 375 degree celsius.?
  9. Chemistry

    Determine the number of moles of N2 that are required to produce 12 mol of NH3 using the equation, N2 + 3H2 --> 2NH3. 12 mol NH3 x 1 mol N2/2 mol NH3 = 6 moles of N2.
  10. Chemistry

    Heating 1.0 mole of ammonia and 1.0 mole of molecular nitrogen at 723k in a 10L flask,the following equilibrium is observed: N2(g)+3H2(g)=2NH3(g) when the equilibrium is reached ,0.40 moles of molecular hydrogen are present in the …

More Similar Questions