Can someone help me figure this out. The difference of two numbers is 80. The second is 8 less than 5 times the first. What are the two numbers?
first write an equation 5x-8=y and then solve it
Tiff gave you part of the solution.
5x-8=y
However, there is the other equation.
x-y=80
Solve one equation for either unknown, then substitute that value for the unknown in the other equation. Once you find that first unknown, solve for the second. Check by substituting the values into both equations.
I hope this helps a little more. Thanks for asking.
To solve this problem, we can use the given information to set up a system of equations. Let's call the first number x and the second number y.
From the first statement, we know that the difference between the two numbers is 80. This can be written as:
y - x = 80
From the second statement, we know that the second number is 8 less than 5 times the first number. This can be written as:
y = 5x - 8
We now have a system of equations:
y - x = 80
y = 5x - 8
To solve for the values of x and y, we can use substitution or elimination method. In this case, let's use the substitution method.
1. Solve the first equation for y:
y = x + 80
2. Substitute this expression for y in the second equation:
x + 80 = 5x - 8
3. Simplify and solve for x:
80 + 8 = 5x - x
88 = 4x
x = 88/4
x = 22
4. Substitute the value of x back into one of the original equations to solve for y:
y = 5(22) - 8
y = 110 - 8
y = 102
So the two numbers are x = 22 and y = 102.