A baseball player hits a triple and ends up on third base. The baseball "diamond" is a square, each side with length 24.2 m, with home plate and the three bases on the four corners. What is the magnitude of his displacement?

* I'm not familiar with the sport

i divided the diamond into two diagonally, then, using the pythagorean theorem I found the hypotenus. but i don't think that is right. Please help

pythagorean theorem is a + b =c

If the 'diamond' is a square, and he's 3/4 round it (3rd base), he's one side length from home. Displacement is'nt how far he went, it's how far he is from the start point. 24.2m.

Well, I have to say, that baseball player must be pretty talented if they managed to hit a triple and end up on third base in a square-shaped diamond! But hey, let's do the math.

Since the diamond is a square, each side has a length of 24.2 m. Now, displacement refers to the straight-line distance between the starting point and the ending point. In this case, the starting point is home plate and the ending point is third base.

If we divide the diamond into two diagonally, as you did, we can see that the baseball player is one side length away from home plate. Therefore, the magnitude of his displacement would be equal to the length of one side of the diamond, which is 24.2 m.

So, the magnitude of his displacement is 24.2 m. Keep swinging for those triples, champ!

To find the magnitude of the player's displacement, you need to determine the distance between the starting point (home plate) and the ending point (third base).

Since the baseball diamond is a square with sides of length 24.2 m, we can conclude that the distance from home plate to first base, from first base to second base, and from second base to third base are all equal to 24.2 m.

Since the player ends up on third base, which is one side length away from home plate, the magnitude of the displacement is equal to the length of one side of the square, which is 24.2 m.

Therefore, the magnitude of the player's displacement is 24.2 meters.

To determine the magnitude of the baseball player's displacement, you can use the Pythagorean theorem. Since the baseball diamond is a square, the distance from home plate to third base is equal to the length of one side of the square which is 24.2 m.

The displacement is the shortest distance between the starting point and the final position, which is from home plate to third base. So, the magnitude of the displacement is equal to 24.2 m.