# calculus

posted by
**Tammy**
.

First I would find the first derivative which is the slope and then would I

plug in the given value into the original equation to find y and then use

y-y_1=m(x-x_1)?

Find the euation of the tangent line at the given value

a) y=ln abs(x+4) x = -3

b) y= (x^2 +5)/(x+1) x=1

a) I found the slope to be 1 and then I got the y-value as ln 1 which

equals 0. so would the equation be y-0= 1(x- -3)?

b) I got the slope as -1/2 and the y-value as 3 so then i got y-3= -1/2

(x-1)

Did I do these problems correctly?

both correct!, good job

are you going to simplify your equations a bit more?

e.g. the first reduces to y=x+3