posted by .

Find the area between the curve y=4/x and the x-axis from x=1 to x=e.

It is a review question for my final exam and I am really stuck on how to solve

You should hope for a final exam question so easy.

area= INT y dx= INT 4/x dx from 1 to e

area= 4ln x from 1 to e

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions


    Sorry the caps lock was on. Can you help me with this pre calculus question. I'm not quite sure how to do this. Here are the instructions. Find the area between each curve and the x-axis for the given interval: y=2x^2+x+1 from x=3 …
  2. Calculus

    Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals?
  3. calculus

    The area enclosed between the x-axis, the curve y=x(2-x) and the ordinates x=1 and x=2 is rotated through 2π radians about x-axis. (a)Calculate the volume of the solid revolution formed. (b)Calculate the rotating area. from this …

    Hi, my exam is tomorrow and I'm here with my girlfriend who's also in the same class trying to figure out how to do the exam review but we're stuck.. please be kind and help us out, we'd really appreciate it. Thank you in advance. …
  5. Calculus

    1. Find the area of the region bounded by the curves and lines y=e^x sin e^x, x=0, y=0, and the curve's first positive intersection with the x-axis. 2. The area under the curve of y=1/x from x=a to x=5 is approximately 0.916 where …
  6. Calculus

    The question is find the area of the reagion that is bounded by the curve y=arctan x, x=0, x=1, and the x-axis. So I've drawn the enclosed region. To find the area would I use the Disc/shell method?
  7. calculus

    find the area enclosed between the x-axis and the curve, if y=x^3+2x^2+x+1 between x=-1 and x=2
  8. calculus

    find the area enclosed between the x-axis and the curve, if y=x^3 and the straight line y=x
  9. Math -Calculus

    Hi, I need help with the problem: "Use a definite integral to find the area of the region under the curve y=6-4x^2 and above the x-axis". I keep getting stuck at 6x-(4x^3/3). Thanks!!
  10. Maths

    Point P in the curve y=x^3 has coordinates (3,27) and PQ is the tangent to the curve at P.Point Q touches the x-axis.Find the area of the region enclosed between the curve, PQ and the x-axis. My answer: I used differenttiation to find …

More Similar Questions