Propane (C3H8) burns in oxygen to produce carbon dioxide and water vapor. The balance equation for this reaction is C3H8 + 5O2 ----> 4H20 + 3CO2. What volume of carbon dioxide id produced when 2.8 L of oxygen are consumed?

Here are the steps for solving stoichiometry problems.
Step 1. Write the balanced chemical equation. You have done that.

Step 2. Convert what you have into mols. Remember 1 mol of a gas @ STP occupies 22.4 L; therefore,
2.8/22.4 =?? mols O2.

Step 3. Use the coefficients in the balanced equation to convert mols of what you have (in this case mols oxygen) to mols of what you want (in this case mols CO2).

Step 4. Convert mols from step 3 to liters by reversing the equation used in step 2.

Post your work if you get stuck.

1.68

Thank You!!! i was stuck on this problem

Well, let's give it a shot!

Step 1: The balanced equation is C3H8 + 5O2 ----> 4H20 + 3CO2.

Step 2: We need to find the number of moles of oxygen consumed, so let's use the formula:

moles = volume / molar volume
moles of O2 = 2.8 L / 22.4 L/mol = 0.125 mol O2

Step 3: Now we can use the coefficients in the balanced equation to convert moles of oxygen to moles of carbon dioxide. From the equation, we know that 5 moles of oxygen react to produce 3 moles of carbon dioxide. So,

moles of CO2 = (0.125 mol O2) * (3 mol CO2 / 5 mol O2) = 0.075 mol CO2

Step 4: Finally, we can convert moles of carbon dioxide to the volume using the molar volume at STP.

volume of CO2 = moles * molar volume
volume of CO2 = 0.075 mol * 22.4 L/mol = 1.68 L

So, when 2.8 L of oxygen are consumed, approximately 1.68 L of carbon dioxide is produced.

I hope that helps!

Step 1: The balanced equation is C3H8 + 5O2 -> 4H2O + 3CO2

Step 2: We are given that 2.8 L of oxygen is consumed. We need to convert this to moles.

Remember that at STP (Standard Temperature and Pressure), 1 mole of gas occupies 22.4 L. Therefore, we can calculate the moles of oxygen.

2.8 L of oxygen * (1 mol/22.4 L) = ~0.125 mol of oxygen

Step 3: Now we can use the coefficients in the balanced equation to convert moles of oxygen to moles of carbon dioxide.

From the balanced equation, we see that the coefficient of oxygen is 5 and the coefficient of carbon dioxide is 3. So, the conversion factor is:

0.125 mol of O2 * (3 mol of CO2/5 mol of O2) = ~0.075 mol of CO2

Step 4: Finally, we need to convert moles of carbon dioxide to liters.

Using the molar volume of a gas at STP, we know that at STP, 1 mole of gas occupies 22.4 L. Therefore, we can calculate the volume of carbon dioxide produced.

0.075 mol of CO2 * (22.4 L/1 mol) = ~1.68 L of CO2

So, when 2.8 L of oxygen are consumed, approximately 1.68 L of carbon dioxide is produced.