A 6 kg rock is suspended by a massless string from one end of a 6m measuring stick. What is the mass of the measuring stick if it is balanced by a support force at the 1m mark? answer in units of kg. Thanks for any help

Rather than just posting the question, you should post your suggested answer or thoughts as well.

Assume that measuring stick is of umiform mass where is the centre of mass? (C)

Use moments

M1 x L1 = M2 x L2

M1=6 kg
L1=1 m
L2= (i.e C - 1 m)

find M2

I'll keep that it mind. Thank you very much!

No problem! Let's continue with the solution.

We know that the center of mass (C) for a uniform mass measuring stick is in the middle. Since the measuring stick is 6m long, the center of mass C is at 3m. Now, we can use the moments equation:

M1 x L1 = M2 x L2

where:
M1 = 6 kg (mass of rock)
L1 = 1 m (distance from support to rock)
M2 = mass of measuring stick (which we want to find)
L2 = (C - 1 m) = (3 m - 1 m) = 2 m (distance from support to center of mass of measuring stick)

Now we can solve for M2:

6 kg * 1 m = M2 * 2 m
6 kg = M2 * 2 kg/m
M2 = 6 kg / 2 kg/m = 3 kg

So the mass of the measuring stick is 3 kg.

To find the mass of the measuring stick, we can use the principle of moments.

Let's set up the equation using the principle of moments:

M1 x L1 = M2 x L2

where:
M1 is the mass of the rock (6 kg)
L1 is the distance from the support point to the rock (1 m)
M2 is the mass of the measuring stick (which we need to find)
L2 is the distance from the support point to the center of mass of the measuring stick

As the balancing force is at the 1 m mark, we can assume that the center of mass of the measuring stick is also at the 1 m mark. Therefore, L2 = 1 m.

Now we can substitute the known values into the equation:

6 kg x 1 m = M2 x 1 m

Simplifying the equation, we get:

6 kg = M2

So the mass of the measuring stick is 6 kg.

To find the mass of the measuring stick, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments is equal to the sum of the anticlockwise moments.

In this case, we have a 6 kg rock suspended from one end of a 6 m measuring stick. The rock exerts a force downward at a distance of 6 m from the support force (at the other end of the measuring stick). The support force provides an upward force at a distance of 1 m from the support force.

Let's denote the mass of the measuring stick as M2 and the center of mass of the measuring stick as C. The clockwise moment due to the rock is equal to the anticlockwise moment due to the support force. We can write this equation as:

M1 x L1 = M2 x L2

Where:
M1 = mass of the rock = 6 kg
L1 = distance of the rock from the support force = 6 m
L2 = distance of the center of mass of the measuring stick from the support force = C - 1 m

Now, let's substitute the known values into the equation:

6 kg x 6 m = M2 x (C - 1 m)

Simplifying the equation:

36 kg·m = M2 x (C - 1 m)

To find the mass of the measuring stick, we need to know the value of C (the center of mass). Unfortunately, that information is not given in the question. Therefore, we cannot determine the exact mass of the measuring stick without knowing the distance of the center of mass from the support force.

So, as of now, we have an equation with two variables. To solve this equation, we would need additional information about the positioning of the center of mass. Without that information, we cannot provide a precise answer to the question.