posted by Mary .
A ball of radius 0.300 m rolls along a horizontal table top with a constant linear speed of 3.30 m/s. The ball rolls off the edge and falls a vertical distance of 2.50 m before hitting the floor. What is the angular displacement of the ball while it is in the air? (All problems in this section assume that there is no slipping of the surfaces in contact during the rolling motion.)
Multiply the rotation rate of the ball, which is (Linear speed)/R, by the time "t" that it takes the ball to hit the ground. Use Y = (1/2) g t^2 for that, and sove for t. Your answer will be in radians.