how many grams of zinc are required to react with excess acid to make one liter of hydrogen at STP?

i have no clue how to go about this i need help

Write the balanced equation.
Zn + 2HCl ==> ZnCl2 + H2

2. Use PV = nRT to convert 1 L H2 gas to mols OR take the shortcut knowing that 1 mol of a gas occupies 22.4 L at STP.

3. Use the equation to convert mols H2 to mols Zn.

4. Then convert mols Zn to grams Zn.
g Zn = mols Zn x atomic mass Zn.

To find the number of grams of zinc required to react with excess acid to produce one liter of hydrogen gas at STP, you can follow these steps:

1. Write the balanced chemical equation for the reaction:
Zn + 2HCl → ZnCl2 + H2

2. Use the ideal gas law equation, PV = nRT, to convert the volume of hydrogen gas to moles:
Since you have one liter of hydrogen gas at STP, you can use the fact that one mole of any gas occupies 22.4 liters at STP. So, 1 liter of hydrogen gas is equal to 1/22.4 moles.

3. From the balanced equation, you can see that 1 mole of Zn reacts with 1 mole of H2. So the number of moles of Zn required will be the same as the number of moles of H2.

4. Now, you need to convert the moles of Zn to grams of Zn. To do this, you can use the molar mass of zinc, which is 65.38 g/mol.

The calculation should look like this:
g Zn = (moles Zn) x (molar mass Zn)

So in your case, the number of grams of zinc required would be:
g Zn = (1/22.4) x (65.38)

Simply substitute the values and calculate to find the answer.