Trigonometic

posted by .

Solving Trigonometic Equations
solve for x : ( by radian)

1)cotx= 3



2)secx = 0.5
<<<and thanks >>>

1) Same as tan x = 1/3. Use a calculator. I get 0.321 radians

2) sec x = 0.5 is not possible. The absolute value of the secant must be one or more.

<< Thanks drwls for your help >>

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. calculus

    find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x …
  2. tan x = 1/2

    Can someone tell me what the radian value is for this number and how they got it?
  3. solving trig. equations

    tan(3x) + 1 = sec(3x) Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes secx and... secx = secx sec(3x) = sec(3x) [just put 3x back in for x- you don't really have to change 3x …
  4. Trigonometic

    Solving Trigonometic Equations 1)sinx = (4/5) 2) cosx = (-12/13) Solving Trigonometic Equations 1)sinx = (4/5) 2) cosx = (-12/13) What is the question?
  5. Trigonometic

    Solving Trigonometic Equations solve for x : 1)sinx = (4/5) 2) cosx = (-12/13) I will do the second one. first of all since the cosine is negative the angle must be in either the second or third quadrants. To find the "angle in standard …
  6. Trigonometic

    Solving Trigonometic Equations solve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 <<<and thanks >>> We know sin 2x = 2(sinx)(cosx) so (sinx)(cos)=1/2(sin 2x) So we can change your equation …
  7. trigonometry

    How do you find: cot(-5pie/4)? you have to know that cotx = 1/tanx so you could just trustfully change your calculator to radians enter 5*pi/4, press =, press +/-, then press Tan, =, then the 1/x key you should get -1 or... you could
  8. Trig

    Verify that each of the following is an identity. tan^2x-sin^2x=tan^2xsin^2x I can get it down to cos^2 on the right, but cannot get it to work out on the left. secx/cosx - tanx/cotx=1 On the left I got down to 1-tan^2, but that clearly …
  9. drwls

    My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to …
  10. math

    Write in terms of cos and sin function. cotx*secx Show work. I know cotx = cosx/sinx and secx = 1/cosx, would that just be the answer or can i solve it?

More Similar Questions