How many electrons are transferred in the reaction of hydrogen peroxide with iron (II) ion in
acidic solution to form iron (III) ion and water?
I am not quite sure what the reaction is, but if you are going from Fe(2+) to Fe(3+), the Fe is losing one electron.
You may be referring to one of the "Fenton's reagent" reactions described at
http://www.h2o2.com/applications/industrialwastewater/fentonsreagent.html
Jessica--I answered this question for you last night AND wrote the two blanced half reactions. The number of electrons transferred in the total reaction is 2.
Trying setting it up like H2O2 + Fe(+2) ----> Fe (+3) + H2O. Try it like that
To determine the number of electrons transferred in the reaction between hydrogen peroxide and iron (II) ion in acidic solution, we need to balance the redox equation.
The balanced equation for this reaction is:
H2O2 + 2 Fe(2+) + 2 H+ → 2 Fe(3+) + 2 H2O
From this equation, we can see that two electrons are transferred per iron (II) ion in the reaction. Each Fe(2+) ion is oxidized to Fe(3+), meaning it loses one electron. Since there are 2 Fe(2+) ions on the reactant side, a total of 2 electrons are transferred in the reaction.
Therefore, the answer to your question is that two electrons are transferred in the reaction between hydrogen peroxide and iron (II) ion in acidic solution to form iron (III) ion and water.