The first step of the synthesis is described by the reaction below. When 1.200 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4, the theoretical yield of FeC2O42H2O is ? grams
im not sure what to do.
do u convert 1.0M to grams first? by multiplying .013 L
thx
First write down the balanced chemical reaction. Then compute the number of moles of Fe(NH4)2(SO4)2 6H2O and H2C2)4 that you start out with. The chemical reaction will tell you how many moles of FeC2O42H2O form per mole of reaatant. You will neded to determine which reactant is the limiting reactant.
hjkm
To find the theoretical yield of FeC2O42H2O, you need to follow these steps:
1. Write down the balanced chemical equation for the reaction:
Fe(NH4)2(SO4)2 6H2O + H2C2O4 → FeC2O42H2O + (NH4)2SO4 + H2SO4
2. Calculate the number of moles of Fe(NH4)2(SO4)2 6H2O:
Given mass of Fe(NH4)2(SO4)2 6H2O = 1.200 g
Molar mass of Fe(NH4)2(SO4)2 6H2O = 392.14 g/mol
Number of moles = given mass / molar mass
Number of moles of Fe(NH4)2(SO4)2 6H2O = 1.200 g / 392.14 g/mol
3. Calculate the number of moles of H2C2O4:
Given volume of H2C2O4 = 13 mL
Convert mL to L by dividing by 1000: 13 mL / 1000 = 0.013 L
Concentration of H2C2O4 = 1.0 M (1.0 mole per liter)
Number of moles of H2C2O4 = concentration * volume
Number of moles of H2C2O4 = 1.0 mol/L * 0.013 L
4. Determine the limiting reactant:
Compare the number of moles of Fe(NH4)2(SO4)2 6H2O and H2C2O4. Whichever reactant has the smaller number of moles is the limiting reactant.
5. Calculate the theoretical yield of FeC2O42H2O:
From the balanced chemical equation, you can see that the stoichiometry of the reaction is 1:1 between Fe(NH4)2(SO4)2 6H2O and FeC2O42H2O. This means that for every mole of Fe(NH4)2(SO4)2 6H2O, you will get 1 mole of FeC2O42H2O.
So, the theoretical yield of FeC2O42H2O is equal to the number of moles of the limiting reactant (either Fe(NH4)2(SO4)2 6H2O or H2C2O4).
6. Convert moles of FeC2O42H2O to grams:
Molar mass of FeC2O42H2O = 265.90 g/mol
Theoretical yield in grams = number of moles of FeC2O42H2O * molar mass of FeC2O42H2O
Remember to perform the calculations with the correct number of significant figures, using appropriate rounding if necessary.