Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I've gotten this far but confused as to what the two intergers are.
5x=3(x+2)=12
5x=3x+2+12
5x=3x+14
2x=14
2x/2x=14/2
x=7
Let n be first integer, so n+2 is the second odd integer.
5n -12= 3(n+2)
5n= 3n+6 + 12
compare this to your work tofind the error.
To find the consecutive odd integers, let's go through the steps of solving the equation correctly:
We are given that 5 times the first integer is 12 more than 3 times the second. Let's set up an equation with n representing the first integer, and n+2 representing the second odd integer.
5n = 3(n+2) + 12
Expanding the equation:
5n = 3n + 6 + 12
Combining like terms:
5n = 3n + 18
Now, let's isolate the variable n. Subtract 3n from both sides of the equation:
2n = 18
Finally, divide by 2:
n = 9
So the first odd integer is 9 and the second odd integer is 9 + 2 = 11.
Therefore, the two consecutive odd integers are 9 and 11.