# Algebra

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Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I've gotten this far but confused as to what the two intergers are.
5x=3(x+2)=12
5x=3x+2+12
5x=3x+14
2x=14
2x/2x=14/2
x=7

Let n be first integer, so n+2 is the second odd integer.

5n -12= 3(n+2)
5n= 3n+6 + 12

compare this to your work tofind the error.

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