calculus
posted by mark .
The base of a solid is a circle of
radius = 4
Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.
I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)
(1/2 * 4 * sqrt12)
I don't know what to do next. If someone knows, I'd be very thankful.
there are like triangles that have vertical bases. They run parallel to the yaxis. The triangles form 2 triangles each that are symmetric to the xaxis.
The equation of the circle is:
x^2 + y^2 = 16
Thanks!
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