rearrange the following equations to make x the subject:
sx2
r= -
2t
6y=9-3x
thaks any ideas would be great
hey , i see u got ur mailing of the ECA as well , i find it hard too
maybe we cod help each other out
yeh i did! it looks quite hard so any help from each other would be great!
ive just sent of TMA 08 and about to start TMA 09 which TMAs did u choose?
To rearrange the given equations to make x the subject, we need to isolate x on one side of the equation. Let's break down each equation step by step:
1. For the equation `r = -sx^2/2t`:
To make x the subject, we need to isolate it. Start by multiplying both sides of the equation by -2t:
r * (-2t) = -sx^2
Next, divide both sides of the equation by -s:
(-2t * r) / -s = x^2
Finally, take the square root of both sides to solve for x:
√[(-2t * r) / -s] = x
So, the rearranged equation with x as the subject is:
x = √[(-2t * r) / -s]
2. For the equation `6y = 9 - 3x`:
To isolate x, start by subtracting 9 from both sides of the equation:
6y - 9 = -3x
Next, divide both sides of the equation by -3:
(6y - 9) / -3 = x
Simplifying further:
x = (9 - 6y) / 3
Therefore, the rearranged equation with x as the subject is:
x = (9 - 6y) / 3
Remember to always check your answers by substituting the values of x back into the original equations to verify their correctness.
Regarding your conversation about studying, it's great to collaborate with others when faced with challenging tasks. You can exchange ideas, discuss concepts, and help each other understand difficult topics. Good luck with your studies!