ALGEBRA 1
posted by DANIELLE .
Solve by whatever Method
1. X^2 +8X = 16
X^2 +8X +16 = 16 +16
(X +4)^2 =0
X+4 =+/ SQRT 0
X=4+/ 0
X=4, X=4
2. 3x^22x5=0
X=b+/ sqrt (b)^24ac
2a a=3 ,b=4,c=5
X=(2)+/ Sqrt (2)^24(3)(5)
2(3)
X=2+/sqrt64 = 2+/8
6
X= 2+8=10/6=1 2/3, x=28=6/6=1
Solution set is 1 2/3, 1
Solve by completing the square
3. X^2x1=0
X^2x=1
X^21/2x=1/2
X^21/2x+ (1/2)^2=1/2 +(1/2)^2
X^2x+1/4=1/2+1/4
(X1/4)^2=1/2
X1/4=+/1/2
x=1/2+/1/2
x=1, x=0
Just want to see if I am on the right path. Thanks Much!!!
#1, OL
#3, look at lines 5 and 6
1/2 + 1/4 = 3/4 not 1/2, take it from there
in #2 you are guilty of "bad form"
you have X= 2+8=10/6=1 2/3, x=28=6/6=1
using the = sign means that whatever you just wrote is equal to the next part.
I see x = 2+8 = 10/6..
2+8 is not equal to 10/6, you can't just drop numbers and then bring them back
that line should have read:
x=(2+8)/6 or x =(28)/6
x=10/6 or x=6/1
x=5/3 or x = 1
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