Trig.......
posted by abdo .
I need to prove that the following is true. Thanks
(2tanx /1tan^x)+(1/2cos^2x1)= (cosx+sinx)/(cosx  sinx)
and thanks ...........
check your typing.
I tried 30º, the two sides are not equal, they differ by 1
oh , thank you Mr Reiny I'll tell my teacher this Question is Wrong .
not necessarily.
look at your first term
what does tan^x mean?
I want you to check what you typed here with your question.
Mr Reiny ,
I tried 30º, the two sides are equal
L.S=3.732
R.S=3.732
Yes, if the term at the bottom is tan^2 x,
you typed tan^x, and I read it as tan x
I got the proof, give me a bit of time to type it
I'm sorry Mr Reiny you are right it is tan^2x .
LS=
2tanx/(1tan^2x) + 1/(2cos^2x 1)
= 2sinx/cosx [1/(1sin^2x/cos^2x)] + 1/(2cos^2x (sin^2x + cos^2x))
=2sinx/cosx [cos2x/(cos^2x  sin^2x)] + 1/(cos^2x  sin^2x) reduce to get same denominator
=2sinxcosx/(cos^2xsin^2x) + 1/(cos^2xsin^2x)
=(2sinxcosx + sin^2x + cos^2x)/(cos^2xsin^2x)
= (cosx+sinx)(cosx+sinx)/[cosx+sinx)(cosxsinx)]
=(cosx+sinx)/(cosx  sinx)
= Right Side!!!!!
thank you Mr Reiny
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