The specific heat capacity of a material is 1200 J/(kg°C). The temperature of 3.0 kg of this solid material is raised by 6.0°C. Ignoring the work that corresponds to the small change in the volume of the material, determine the change in the internal energy of the material.
Wouldn't it be mcdeltat
Thank you!
Yes, you are correct! The change in the internal energy of a material can be determined using the equation:
ΔU = mcΔT
Where:
ΔU is the change in internal energy
m is the mass of the material
c is the specific heat capacity of the material
ΔT is the change in temperature
In this case, the given values are:
m = 3.0 kg (mass of the material)
c = 1200 J/(kg°C) (specific heat capacity of the material)
ΔT = 6.0°C (change in temperature)
Substituting these values into the equation:
ΔU = (3.0 kg)(1200 J/(kg°C))(6.0°C)
Now, you can calculate the change in internal energy by multiplying the numbers together:
ΔU = 21,600 J
So, the change in the internal energy of the material is 21,600 joules.