# math

posted by .

Baseball

Nick throws a baseball upward with an initial velocity of 60 feet per second. What is the maximum height of the ball after Nick releases the ball?

Formula for the problem - h(t)=v0t-16t^2, h(t)= the height of an object in feet, v0=an object's initial velocity in feet per second, and t= time in seconds

but you know the initial velocity
so h(t) = 60t - 16t^2

If you are studying calculus, differentiate, set the derivative equal to zero and solve for t
Substitute the t value back in your equation.

If you don't know Calculus, use the method of completing the square, I hope you know what i mean by that.

I don't know what you mean by that

## Similar Questions

1. ### calculus

A baseball pitcher throws a baseball with an initial velocity of 133 feet per second at an angle of 20° to the hoizontal. The ball leaves the pitcher's hand at a height of 5 feet. Find parametric equations that descrive the motion …
2. ### ap calculus

The height s of a ball, in feet, thrown with an initial velocity of 112 feet per second from an initial height of 6 feet is given as a function of time t (in seconds) by s(t)=-16t^2+112t+20. 1. What is the maximum height of the ball?
3. ### algebra

A baseball player releases a baseball at the height of 7 feet above the ground with an initial vertical velocity of 54 feet per second. How long will it take the ball to reach the ground?
4. ### math

a baseball is hit with an initial velocity of 75 feet per second from the height of 3 feet. The function h(t)=-16t squared + 75t + 3 models the path of the baseball where t represents the time in seconds that the ball has been traveling …
5. ### Algebra

A baseball player hits a baseball into the air with an initial vertical velocity of 48 feet per second from a height of 3 feet. 8. Write an equation that gives the baseball’s height as a function of the time (in seconds) after it …
6. ### Alg 1

A baseball player hit a ball with an upward velocity of 46 ft/s. Its height h is feet after t seconds is given by the function h = -16t^2 + 46t + 6. What is the maximum height the ball reaches?
7. ### PreCalculas

A ball is thrown upward with an initial velocity of 4 ft/sec from a height of 10 feet. What is the maximum height that the ball will reach?
8. ### Pre-Cal

A baseball player throws baseball at a velocity 139ft per second at an angle of 20 degrees. The ball leaves the players hand at a height of 5 feet. The path of the ball has a parametric equation x=v(o)t cos(o) and y-h+v(o)tsin(o)-16t^2. …
9. ### Math

In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of …
10. ### Maths

object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of time in seconds after the ball was thrown. Also, …

More Similar Questions