Two perpendicular diamters(cutting each other at right angles) of a circle cut the circumference at four(4) points. A square is formed by joining the 4 points. If the circumference of the circle is 132cm, find the area of the square.

so right here they tell me first to find the radius of the circle...2 times pi times r?

2pi r=132
r=66/pi or diameter=132/pi

The area of a rhombus (a square is a rhombus) is the product of its diagonals
so the area = (132/pi)(132/pi) =

To find the radius of the circle, we can follow the given equation: 2πr = 132.

Divide both sides of the equation by 2π: r = 132 / (2π) = 66 / π.

Next, we need to find the diameter of the circle, which is simply twice the radius: diameter = 2 * (66 / π) = 132 / π.

Since the four points where the diameters intersect the circumference form a square, the sides of the square are equal to the diameter of the circle.

Therefore, the side length of the square = 132 / π.

To find the area of the square, we can use the formula for the area of a square, which is the side length squared.

Area of the square = (side length)^2 = (132 / π)^2.