High-heeled shoes can cause tremendous pressure to be applied to the floor. Suppose the radius of a heel is 6.00 10-3 m. At times during a normal walking motion, nearly the entire body weight acts perpendicular to the surface of such a heel. Find the pressure that is applied to the floor under the heel because of the weight of a 65.0 kg woman.

P = Weight/Area = M g / (pi R^2)

Do the numbers. g is the accelerwtion of gravity

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To find the pressure applied to the floor, we use the formula:

Pressure (P) = Weight/Area

Given that the weight of the woman is 65.0 kg and the radius of the heel is 6.00 x 10^-3 m:

Weight (W) = mass x gravity
W = 65.0 kg x 9.8 m/s^2 (acceleration due to gravity)
W = 637.0 N (Newtons)

Area (A) = pi x radius^2
A = pi x (6.00 x 10^-3 m)^2
A = 3.14 x (6.00 x 10^-3 m)^2
A = 3.14 x 3.6 x 10^-5 m^2
A ≈ 1.131 x 10^-4 m^2

Now we can substitute the values into the formula to find the pressure:

P = 637.0 N / (1.131 x 10^-4 m^2)
P ≈ 5.63 x 10^6 Pascal (Pa)

The pressure applied to the floor under the heel is approximately 5.63 x 10^6 Pa.

To find the pressure applied to the floor under the heel, we first need to find the weight of the woman.

Weight = mass * acceleration due to gravity
Weight = 65.0 kg * 9.8 m/s^2 = 637 N (Newtons)

Now we can use the formula for pressure:

Pressure = Weight / Area

The area of the heel can be found using the formula for the area of a circle:

Area = pi * radius^2
Area = pi * (6.0 * 10^-3 m)^2 = 1.13 * 10^-4 m^2

Substituting the values into the pressure formula:

Pressure = 637 N / (1.13 * 10^-4 m^2)
Pressure = 5.64 * 10^6 N/m^2

So, the pressure applied to the floor under the heel due to the weight of the woman is approximately 5.64 * 10^6 N/m^2.

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