i have to decide which one is more polar by using an arrow.
1. N-H
2. O-F
3.C-O
Look up the electronegativity on a chart and take the difference between the two elements. The larger the difference the more polar.
To determine which molecule is more polar, we need to compare the electronegativity values of the elements. Electronegativity is the ability of an atom to attract electrons towards itself in a covalent bond.
The greater the difference in electronegativity between two atoms, the more polar the bond becomes. We can look up the electronegativity values on an electronegativity chart.
1. N-H: Nitrogen (N) has an electronegativity of 3.04, and hydrogen (H) has an electronegativity of 2.20. The difference in electronegativity is 3.04 - 2.20 = 0.84.
2. O-F: Oxygen (O) has an electronegativity of 3.44, and fluorine (F) has an electronegativity of 3.98. The difference in electronegativity is 3.44 - 3.98 = -0.54.
3. C-O: Carbon (C) has an electronegativity of 2.55, and oxygen (O) has an electronegativity of 3.44. The difference in electronegativity is 2.55 - 3.44 = -0.89.
To summarize, the larger the difference in electronegativity, the more polar the bond. Based on the calculated differences, the order of increasing polarity is:
1. C-O (-0.89)
2. O-F (-0.54)
3. N-H (0.84)
Therefore, the most polar bond of the three is N-H.