a 45.8mL sample of a 5.8 M KNO3 solution is diluted to 1.00L. What volume of the diluted solution contains 15.0g KNO3?
how do you do this?
moles of solution: 5.8*.0458 moles
Grams of solute= moles*molmassKNO3
Volume of 15g= 1000ml*15/gramssoluteabove
To find the volume of the diluted solution that contains 15.0g of KNO3, you can follow these steps:
1. Calculate the number of moles of the original solution:
Moles of original solution = concentration * volume (in liters)
Given that the concentration is 5.8 M and the volume is 45.8 mL, convert the volume to liters by dividing it by 1000:
Volume in liters = 45.8 mL / 1000 = 0.0458 L
Moles of original solution = 5.8 M * 0.0458 L = 0.26564 moles
2. Calculate the molar mass of KNO3:
KNO3 consists of potassium (K), nitrogen (N), and oxygen (O). The molar masses are:
Molar mass of K = 39.10 g/mol
Molar mass of N = 14.01 g/mol
Molar mass of O = 16.00 g/mol
Multiply the molar masses by their respective subscripts to find the total molar mass of KNO3:
Molar mass of KNO3 = (1 * 39.10) + (1 * 14.01) + (3 * 16.00) = 101.11 g/mol
3. Calculate the grams of solute in the original solution:
Grams of solute = moles of solution * molar mass of KNO3
Grams of solute = 0.26564 moles * 101.11 g/mol = 26.86 g
4. Use the grams of solute to find the volume of the diluted solution:
Volume of 15g = (1000 mL * 15 g) / grams of solute
Volume of 15g = 1000 mL * 15 g / 26.86 g = 557.21 mL
Therefore, the volume of the diluted solution that contains 15.0g of KNO3 is approximately 557.21 mL.